3.1447 \(\int \frac{(a+b x)^5}{(a c+b c x)^{3/2}} \, dx\)

Optimal. Leaf size=22 \[ \frac{2 (a c+b c x)^{9/2}}{9 b c^6} \]

[Out]

(2*(a*c + b*c*x)^(9/2))/(9*b*c^6)

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Rubi [A]  time = 0.0043641, antiderivative size = 22, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.1, Rules used = {21, 32} \[ \frac{2 (a c+b c x)^{9/2}}{9 b c^6} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*x)^5/(a*c + b*c*x)^(3/2),x]

[Out]

(2*(a*c + b*c*x)^(9/2))/(9*b*c^6)

Rule 21

Int[(u_.)*((a_) + (b_.)*(v_))^(m_.)*((c_) + (d_.)*(v_))^(n_.), x_Symbol] :> Dist[(b/d)^m, Int[u*(c + d*v)^(m +
n), x], x] /; FreeQ[{a, b, c, d, n}, x] && EqQ[b*c - a*d, 0] && IntegerQ[m] && ( !IntegerQ[n] || SimplerQ[c +
d*x, a + b*x])

Rule 32

Int[((a_.) + (b_.)*(x_))^(m_), x_Symbol] :> Simp[(a + b*x)^(m + 1)/(b*(m + 1)), x] /; FreeQ[{a, b, m}, x] && N
eQ[m, -1]

Rubi steps

\begin{align*} \int \frac{(a+b x)^5}{(a c+b c x)^{3/2}} \, dx &=\frac{\int (a c+b c x)^{7/2} \, dx}{c^5}\\ &=\frac{2 (a c+b c x)^{9/2}}{9 b c^6}\\ \end{align*}

Mathematica [A]  time = 0.0148942, size = 25, normalized size = 1.14 \[ \frac{2 (a+b x)^6}{9 b (c (a+b x))^{3/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x)^5/(a*c + b*c*x)^(3/2),x]

[Out]

(2*(a + b*x)^6)/(9*b*(c*(a + b*x))^(3/2))

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Maple [A]  time = 0.001, size = 23, normalized size = 1.1 \begin{align*}{\frac{2\, \left ( bx+a \right ) ^{6}}{9\,b} \left ( bcx+ac \right ) ^{-{\frac{3}{2}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^5/(b*c*x+a*c)^(3/2),x)

[Out]

2/9*(b*x+a)^6/b/(b*c*x+a*c)^(3/2)

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Maxima [A]  time = 0.977158, size = 24, normalized size = 1.09 \begin{align*} \frac{2 \,{\left (b c x + a c\right )}^{\frac{9}{2}}}{9 \, b c^{6}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^5/(b*c*x+a*c)^(3/2),x, algorithm="maxima")

[Out]

2/9*(b*c*x + a*c)^(9/2)/(b*c^6)

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Fricas [B]  time = 2.07865, size = 120, normalized size = 5.45 \begin{align*} \frac{2 \,{\left (b^{4} x^{4} + 4 \, a b^{3} x^{3} + 6 \, a^{2} b^{2} x^{2} + 4 \, a^{3} b x + a^{4}\right )} \sqrt{b c x + a c}}{9 \, b c^{2}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^5/(b*c*x+a*c)^(3/2),x, algorithm="fricas")

[Out]

2/9*(b^4*x^4 + 4*a*b^3*x^3 + 6*a^2*b^2*x^2 + 4*a^3*b*x + a^4)*sqrt(b*c*x + a*c)/(b*c^2)

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Sympy [A]  time = 1.3438, size = 73, normalized size = 3.32 \begin{align*} \begin{cases} \frac{2 b^{\frac{7}{2}} \left (\frac{a}{b} + x\right )^{\frac{9}{2}}}{9 c^{\frac{3}{2}}} & \text{for}\: \left |{\frac{a}{b} + x}\right | > 1 \vee \left |{\frac{a}{b} + x}\right | < 1 \\\frac{b^{\frac{7}{2}}{G_{2, 2}^{1, 1}\left (\begin{matrix} 1 & \frac{11}{2} \\\frac{9}{2} & 0 \end{matrix} \middle |{\frac{a}{b} + x} \right )}}{c^{\frac{3}{2}}} + \frac{b^{\frac{7}{2}}{G_{2, 2}^{0, 2}\left (\begin{matrix} \frac{11}{2}, 1 & \\ & \frac{9}{2}, 0 \end{matrix} \middle |{\frac{a}{b} + x} \right )}}{c^{\frac{3}{2}}} & \text{otherwise} \end{cases} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**5/(b*c*x+a*c)**(3/2),x)

[Out]

Piecewise((2*b**(7/2)*(a/b + x)**(9/2)/(9*c**(3/2)), (Abs(a/b + x) > 1) | (Abs(a/b + x) < 1)), (b**(7/2)*meije
rg(((1,), (11/2,)), ((9/2,), (0,)), a/b + x)/c**(3/2) + b**(7/2)*meijerg(((11/2, 1), ()), ((), (9/2, 0)), a/b
+ x)/c**(3/2), True))

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Giac [B]  time = 1.06055, size = 359, normalized size = 16.32 \begin{align*} \frac{2 \,{\left (315 \, \sqrt{b c x + a c} a^{4} - \frac{420 \,{\left (3 \, \sqrt{b c x + a c} a c -{\left (b c x + a c\right )}^{\frac{3}{2}}\right )} a^{3}}{c} + \frac{126 \,{\left (15 \, \sqrt{b c x + a c} a^{2} c^{2} - 10 \,{\left (b c x + a c\right )}^{\frac{3}{2}} a c + 3 \,{\left (b c x + a c\right )}^{\frac{5}{2}}\right )} a^{2}}{c^{2}} - \frac{36 \,{\left (35 \, \sqrt{b c x + a c} a^{3} c^{3} - 35 \,{\left (b c x + a c\right )}^{\frac{3}{2}} a^{2} c^{2} + 21 \,{\left (b c x + a c\right )}^{\frac{5}{2}} a c - 5 \,{\left (b c x + a c\right )}^{\frac{7}{2}}\right )} a}{c^{3}} + \frac{315 \, \sqrt{b c x + a c} a^{4} c^{4} - 420 \,{\left (b c x + a c\right )}^{\frac{3}{2}} a^{3} c^{3} + 378 \,{\left (b c x + a c\right )}^{\frac{5}{2}} a^{2} c^{2} - 180 \,{\left (b c x + a c\right )}^{\frac{7}{2}} a c + 35 \,{\left (b c x + a c\right )}^{\frac{9}{2}}}{c^{4}}\right )}}{315 \, b c^{2}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^5/(b*c*x+a*c)^(3/2),x, algorithm="giac")

[Out]

2/315*(315*sqrt(b*c*x + a*c)*a^4 - 420*(3*sqrt(b*c*x + a*c)*a*c - (b*c*x + a*c)^(3/2))*a^3/c + 126*(15*sqrt(b*
c*x + a*c)*a^2*c^2 - 10*(b*c*x + a*c)^(3/2)*a*c + 3*(b*c*x + a*c)^(5/2))*a^2/c^2 - 36*(35*sqrt(b*c*x + a*c)*a^
3*c^3 - 35*(b*c*x + a*c)^(3/2)*a^2*c^2 + 21*(b*c*x + a*c)^(5/2)*a*c - 5*(b*c*x + a*c)^(7/2))*a/c^3 + (315*sqrt
(b*c*x + a*c)*a^4*c^4 - 420*(b*c*x + a*c)^(3/2)*a^3*c^3 + 378*(b*c*x + a*c)^(5/2)*a^2*c^2 - 180*(b*c*x + a*c)^
(7/2)*a*c + 35*(b*c*x + a*c)^(9/2))/c^4)/(b*c^2)